\(Zn+2HCl-->ZnCl2+H2\)
\(nHCl=0,4.1=0,4\left(mol\right)\)
\(n_{Zn}=\frac{1}{2}n_{HCl}=0,2\left(mol\right)\)
\(m_{Zn}=0,2.65=13\left(g\right)< 14,08\)
--->sau pư chỉ có dd ZnCl2
\(n_{ZnCl2}=\frac{1}{2}n_{HCl}=0,2\left(mol\right)\)
\(m_{ZnCl2}=0,2.136=27,2\left(g\right)\)