\(\text{Mg+2HCl=MgCl2+H2 (1) }\)
\(\text{FeO+2HCl=FeCl2+H2O (2)}\)
nH2=nMg=3,36/22,4=0,15mol
=>mMg=0,15.24=3,6g
=>mFeO=20,4-3,6=16,8g
\(\text{nHCl (1)=2nMg=0,3mol}\)
\(\text{nHCl (2)=2nFeO=2.(16,8/72)= 7/15mol}\)
=> nHCl pu=0,3+ 7/15= 23/30 mol
=> CM HCl= (23/30)/0,3=2,56M