2NaOH+CO2---->Na2CO3+H2O(1)
CO2+Na2CO3+H2O---->2NaHCO3(2)
Ta có
m\(_{NaOH}=\frac{200.10}{100}=20\left(g\right)\)
n\(_{NaOH}=\frac{20}{40}=0,5\left(mol\right)\)
n\(_{CO2}=\frac{22,4}{22,4}=1\left(mol\right)\)
=>CO2 du2..Tạo 2 muối
Theo pthh1
n\(_{Na2CO3}=\frac{1}{2}n_{NaOH}=0,25\left(mol\right)\)
m\(_{Na2CO3}=0,25.106=26,5\left(g\right)\)
n\(_{CO2}=\frac{1}{2}n_{NaOH}=0,25\left(mol\right)\)
n\(_{CO2}\left(pt2\right)=1-0,25=0,75\left(mol\right)\)
Theo pthh2
n\(_{NaHCO3}=2n_{CO2}=1,5\left(mol\right)\)
m\(_{NaHCO3}=1,5.84=126\left(g\right)\)
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