PTHĐGD là:
(2m-2)x+1-2m=1/2(1-m)x+3/2(1-m)
=>\(\Leftrightarrow x\left(2m-2-\dfrac{1}{2\left(1-m\right)}\right)=\dfrac{3}{2\left(1-m\right)}-1+2m\)
\(\Leftrightarrow x\cdot\left(\dfrac{4\left(m-1\right)\left(m-1\right)+1}{2\left(m-1\right)}\right)=\dfrac{3+2\left(1-m\right)\left(-1+2m\right)}{2\left(1-m\right)}\)
\(\Leftrightarrow x\cdot\dfrac{4m^2-8m+4+1}{2\left(m-1\right)}=\dfrac{3+\left(2-2m\right)\left(2m-1\right)}{2\left(1-m\right)}\)
\(\Leftrightarrow x=\dfrac{3-4m-2-4m^2+2m}{4m^2-8m+4}=\dfrac{-4m^2-2m+1}{4m^2-8m+4}\)
=>\(y=\left(2m-2\right)\cdot\dfrac{-4m^2-2m+1}{4\left(m-1\right)^2}+1-2m\)
\(=\dfrac{2\left(m-1\right)\left(-4m^2-2m+1\right)}{4\left(m-1\right)^2}+1-2m\)
\(=\dfrac{-4m^2-2m+1}{2\left(m-1\right)}+\left(-2m+1\right)\)
\(=\dfrac{-4m^2-2m+1+\left(-2m+1\right)\cdot\left(2m-2\right)}{2\left(m-1\right)}\)
\(=\dfrac{-4m^2-2m+1-4m^2+4m-2m+2}{2\left(m-1\right)}\)
\(=\dfrac{-8m^2+3}{2\left(m-1\right)}\)
