\(n_{Al}=\dfrac{1,8}{27}=\dfrac{1}{15}mol\)
\(2Al+6H_2O\rightarrow2Al\left(OH\right)_3+3H_2\)
\(Al\left(OH\right)_3+KOH_{dư}\rightarrow KAlO_2+H_2O\)
\(\Rightarrow2Al+2KOH+2H_2O\rightarrow2KAlO_2+3H_2\)
\(\dfrac{1}{15}\) \(\rightarrow\) \(0,1\)
\(V=0,1\cdot22,4=2,24l\)