\(2K+2H_2O\rightarrow2KOH+H_2\uparrow\)
\(K_2O+H_2O\rightarrow2KOH\)
\(n_{H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)
\(\Rightarrow n_K=2n_{H_2}=2.0,1=0,2\left(mol\right)\)
\(m_K=0,2.39=7,8\left(g\right)\)
\(m_{K_2O}=17,2-7,8=9,4\left(g\right)\)
\(m_{ddspu}=7,9+83=90,9\left(g\right)\)
\(C\%=\dfrac{9,4}{90,9}.100\%=10,34\%\)