Ankin : CnH2n-2
\(n_{CO_2} = \dfrac{0,448}{22,4}=0,02(mol)\\ c_nH_{2n-2} + \dfrac{3n-1}{2}O_2 \xrightarrow{t^o} nCO_2 + (n-1)H_2O\\ n_{ankin} = \dfrac{n_{CO_2}}{n}=\dfrac{0,02}{n}(mol)\\ \Rightarrow \dfrac{0,02}{n}(14n-2) = 1,08\\ \Rightarrow n = -0,05<0\)
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