a) Mg+2HCl--->MgCl2+H2
MgO+2HCl--->MgCl2+H2
b) Ta có
n H2=2,24/22,4=0,1(mol)
Theo pthh1
n Mg=n H2=0,1(mol)
m Mg=0,1.24=2,4(g)
m MgO=10,4-2,4=8(g)
c) Theo pthh1
n HCl=2n H2=0,2(mol)
Ta có
n MgO=8/40=0,2(mol)
Theo pthh2
n HCl=2n MgO=0,4(mol)
Tổng n HCl=0,4+0,2=0,6(mol)
V HCl=0,/2=0,3(l)