Hình tự vẽ nha !
a, Xét \(\Delta DOC\) và \(\Delta BOA\) có:
\(\widehat{DOC}=\widehat{AOB}\left(đ.đỉnh\right)\)
\(\widehat{CDO}=\widehat{OBA}\left(so-le-trong\right)\)
\(\Rightarrow\Delta DOC~\Delta BOA\left(g-g\right)\)
\(\Rightarrow\frac{DO}{BO}=\frac{OC}{OA}=\frac{CD}{AB}\)
\(\Rightarrow OC=\frac{DO.OA}{BO}=\frac{3.12}{9}=4cm\)
\(\Rightarrow CD=\frac{DO.AB}{BO}=\frac{3.18}{9}=6cm\)
Vậy ...............