Đặt \(A=\dfrac{3}{8}xy^3z\cdot\left(-12xy\right)\)
\(=\dfrac{3}{8}\cdot\left(-12\right)\cdot xy^3z\cdot xy\)
\(=-\dfrac{36}{8}x^2y^4z\)
\(=-\dfrac{9}{2}x^2y^4z\)
Thay x=1/2;y=2;z=-3 vào A, ta được:
\(A=-\dfrac{9}{2}\cdot\left(\dfrac{1}{2}\right)^2\cdot2^4\cdot\left(-3\right)\)
\(=\dfrac{27}{2}\cdot\dfrac{1}{4}\cdot16=27\cdot2=54\)
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