1)cho a,b,c >0. \(cmr:\dfrac{1}{a^2+bc}+\dfrac{1}{b^2+ca}+\dfrac{1}{c^2+ab}\le\dfrac{a+b+c}{2abc}\)
2) cho a,b,c>0 và a+b+c=1. \(cmr:\left(1+\dfrac{1}{a}\right)\left(1+\dfrac{1}{b}\right)\left(1+\dfrac{1}{c}\right)\ge64\)
3) cho a,b,c>0. \(cme:\dfrac{a^2}{b^2}+\dfrac{b^2}{c^2}+\dfrac{c^2}{a^2}\ge\dfrac{a}{b}+\dfrac{b}{c}+\dfrac{c}{a}\)
4) cho a,b,c>0 .\(cmr:\dfrac{a^3}{b^3}+\dfrac{b^3}{c^3}+\dfrac{c^3}{a^3}\ge\dfrac{a^2}{b^2}+\dfrac{b^2}{c^2}+\dfrac{c^2}{a^2}\)
5)cho a,b,c>0. cmr: \(\dfrac{1}{a\left(a+b\right)}+\dfrac{1}{b\left(b+c\right)}+\dfrac{1}{c\left(c+a\right)}\ge\dfrac{27}{2\left(a+b+c\right)^2}\)
Cho a, b, c > 0. CMR \(\dfrac{1}{a\left(a+1\right)}+\dfrac{1}{b\left(b+1\right)}+\dfrac{1}{c\left(c+1\right)}\ge\dfrac{3}{\sqrt[3]{abc}\left(1+\sqrt[3]{abc}\right)}\)
Cho a, b, c > 0 và abc = 1. Chứng minh rằng \(\dfrac{1}{a^2.\left(b+c\right)}+\dfrac{1}{b^2.\left(c+a\right)}+\dfrac{1}{c^2.\left(a+b\right)}\ge\dfrac{3}{2}\)
Cho a,b,c>0 thỏa mãn abc=1. Chứng minh:
\(\dfrac{a^2}{b^2}+\dfrac{b^2}{c^2}+\dfrac{c^2}{a^2}\ge\dfrac{2}{3}\left[\dfrac{1}{a^3bc\left(b^2+1\right)}+\dfrac{1}{b^3ca\left(c^2+1\right)}+\dfrac{1}{c^3ab\left(a^2+1\right)}\right]\).
cho a,b,c là các số thực dương. Cmr
\(\dfrac{a^4}{b^3\left(c+a\right)}+\dfrac{b^4}{c^3\left(a+b\right)}+\dfrac{c^4}{a^3\left(b+c\right)}\ge\dfrac{3}{2}\)
Cho a;b;c là 3 cạnh tam giác. CHứng minh: \(\dfrac{1}{\left(a+b-c\right)^2}+\dfrac{1}{\left(a-b+c\right)^2}+\dfrac{1}{\left(-a+b+c\right)^2}\ge\dfrac{1}{a^2}+\dfrac{1}{b^2}+\dfrac{1}{c^2}\)
Cho \(a;b;c\) là các số thực dương thỏa mãn :\(0< a;b;c< 1\). Chứng minh rằng:
\(\dfrac{1}{a.\left(1-b\right)}+\dfrac{1}{b.\left(1-c\right)}+\dfrac{1}{c.\left(1-a\right)}\ge\dfrac{3}{1-\left(a+b+c\right)+ab+bc+ac}\)
P/s: Đề cương toán lớp 10 trường THPT chuyên sư phạm Hà Nội.
Em xin nhờ quý thầy cô giáo và các bạn giúp đỡ, em cám ơn nhiều ạ!
CM: \(\dfrac{1}{a\left(b+1\right)}+\dfrac{1}{b\left(c+1\right)}+\dfrac{1}{c\left(a+1\right)}\ge\dfrac{3}{1+abc}\) với a,b,c \(\ge\) 1. Help!
cho a,b,c > 0 thỏa mãn \(a^2+b^2+c^2=3\)
CMR \(P=\sqrt{\dfrac{9}{\left(a+b\right)^2}+c^2}+\sqrt{\dfrac{9}{\left(b+c\right)^2}+a^2}+\sqrt{\dfrac{9}{\left(c+a\right)^2}+b^2}\ge\dfrac{3\sqrt{13}}{2}\)