\(3HCl+2CO2-->2O2+C2H3Cl3\)
\(n_{CO2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(n_{HCl}=\frac{3}{2}n_{CO2}=0,3\left(mol\right)\)
\(m_{HCl}=0,2.36,5=7,3\left(g\right)\)
\(m_{ddHCl}=\frac{7,3.100}{20}=36,5\left(g\right)\)
100ml để làm j nhỉ??
nCO2=4,48\22,4=0,2(mol)
3HCl+2CO2−−>2O2+C2H3Cl3
0,3------0,2 mol
->mHCl=0,2.36,5=7,3(g)
==>mddHCl=7,3.100\20=36,5(g)