\(v_0=30\)km/h=\(\dfrac{25}{3}m\)/s
Gia tốc tàu:
\(v^2-v_0^2=2aS\Rightarrow a=\dfrac{v^2-v_0^2}{2S}=\dfrac{\left(\dfrac{25}{3}\right)^2-0}{2\cdot500}=\dfrac{5}{72}\)(m/s2)
Thời gian tăng tốc:
\(v=v_0+at\Rightarrow t=\dfrac{v-v_0}{a}=\dfrac{\dfrac{25}{3}}{\dfrac{5}{72}}=120s=2'\)