Giải:
Ta có:
\(2016^{\left(x-1\right)\left(x+2\right)}=1\)
\(2016^{\left(x-1\right)\left(x+2\right)}=2016^0\)
Vì \(2016=2016\)
Nên \(\left(x-1\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)
Vậy \(x=1\) hoặc \(x=-2\).
Chúc bạn học tốt!
: 2016(X-1).(X+2)=1
=2016(x-1)(x+2)=20160
=> (x-1)(x+2)=0
=> \(\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)
vậy x=1 hoặc x=-2