Đề cho 200 ml dd axit nồng độ bao nhiêu bạn nhỉ?
Ta có: \(n_{H_2SO_4}=0,2.1,5=0,3\left(mol\right)\)
PT: \(2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O\)
Theo PT: \(n_{KOH}=2n_{H_2SO_4}=0,6\left(mol\right)\)
\(\Rightarrow m_{KOH}=0,6.56=33,6\left(g\right)\Rightarrow m_{ddKOH}=\dfrac{33,6}{5,6\%}=600\left(g\right)\)
\(\Rightarrow V_{ddKOH}=\dfrac{600}{1,045}\approx574,16\left(ml\right)\)