Question

BT1: Tính

1) \(3\dfrac{1}{2}+15\dfrac{4}{9}:\dfrac{26}{7}-2\dfrac{4}{9}:\dfrac{26}{7}\)

2) \(34.\left(2\dfrac{1}{17}-3\dfrac{5}{24}\right)+\dfrac{1}{2}\)

Answer 1

\(3\dfrac{1}{2}+15\dfrac{4}{9}:\dfrac{26}{7}-2\dfrac{4}{9}:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\dfrac{139}{9}:\dfrac{26}{7}-\dfrac{22}{9}:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\left(\dfrac{139}{9}-\dfrac{22}{9}\right):\dfrac{26}{7}\)

\(=\dfrac{7}{2}+13:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\dfrac{7}{2}\)

\(=7.\)

Answer 2

\(3\dfrac{1}{2}+15\dfrac{4}{9}:\dfrac{26}{7}-2\dfrac{4}{9}:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+\dfrac{139}{9}:\dfrac{26}{7}-\dfrac{22}{9}:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+\left(\dfrac{139}{9}-\dfrac{22}{9}\right):\dfrac{26}{7}\)

=\(\dfrac{7}{2}+13:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+13.\dfrac{7}{26}\)

=\(\dfrac{7}{2}+\dfrac{7}{2}\)

= 7