Question

Bỏ dấu ngoặc rồi tính hợp lý:

a) (12-46)+(46+88)

b) (14+67)+(33-14+100)

c) (35+12-47)-(12+53+65)

Answer 1

a) (12-46)+(46+88)

= 12-46+46+88

= (12+88)+[(-46)+46]

= 100+0

=100.

b) (14+67)+(33-14+100)

= 14+67+33-14+100

=[ [14+(-14)]+[(67+33)+100]

= 0+200

= 200.

c) (35+12-47)-(12+53+65)

= 35+12-47-12-53-65

=[12+(-12)]+[(-47)+(-53)]+[35+(-65)]

=0+(-100)+(-30)

=(-100)+(-30)

=-130.

Chúc bạn học tốt !!!

Answer 2

a) (12-46)+(46+88)=12-46+46+88

=(12+88)-(46-46)=100

b) (14+67)+(33-14+100)=14+67+33-14+100

=(14-14)+100+(67+33)=100+100=200

c) (35+12-47)-(12+53+65)=35+12-47-12-53-65

=(12-12)-(47+53)-(65-35)= -100-30

=-130