Question

. Biết

. R₁=25

R₂=35

R₃=65

R₄=15

R₅=10

. U_AB=45V

. Tính I_1, I₂, I₃, I₄, I₅?

Answer 1

R₂₃=R₂+R₃=35+65=100Ω

R₄₅=R₄+R₅= 15+10=25Ω

R_m=R₁+(R₂₃.R₄₅)/(R₂₃+R₄₅)=45Ω

I_m=I₁=U_AB/R_m=1A

I₂₃=I₂=I₃=[R₄₅/(R₂₃+R₄₅)].I_m=0,2A

I₄₅=I₄=I₅=I_m-I₂₃=0,8A

Answer 2

Ta có:

(R₂ntR₃)//(R₄ntR₅)]ntR₁

R₂₃=R₂+R₃=35+65=100Ω)

R₄₅=R₄+R₅=15+10=25(Ω)

R_td=\(R_1+\dfrac{R_{23}.R_{34}}{R_{23}+R_{34}}=25+\dfrac{100.25}{100+25}=45\left(\text{Ω}\right)\)

=>I=I₁=\(\dfrac{U}{R_{td}}=\dfrac{45}{45}=1\left(A\right)\)

I₂=I₃=\(I\dfrac{R_4R_5}{R_2+R_3+R_4+R_5}=1\dfrac{15+10}{35+65+15+10}=\dfrac{25}{125}=0,2\left(A\right)\)

I₄=I₅=I-I₂₃=1-0,2=0,8(A)