Question

Bài 6 . Tìm x

\(1+2+3+...+x=4950\)    

giúp mk zới mấy  bn , mk mà ko có bài nộp là mk bị phạt í 

Answer 1

\(1+2+3+...+x=4950\)

\(\Rightarrow\left(x+1\right)x=4950.2\)

\(\Rightarrow\left(x+1\right)x=9900\)

\(\Rightarrow\left(x+1\right)x=99.100\)

\(\Rightarrow x=99\)

Vậ x= 99

Answer 2

\(1+2+3+...+x=4950\)

\(\left(1+x\right).\frac{x}{2}=4950\)

\(\left(1+x\right).x=4950.2\)

\(\left(1+x\right).x=9900\)

\(\left(1+x\right).x=99.100\)

\(\Rightarrow x=100\)

Answer 3

(x+1)=9900

(x+1)x=99100

suy ra x=99