Question

Bài 3 ạ..

Answer 1

a) \(a,\dfrac{x-3}{x+3}=\dfrac{\left(x-3\right)\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{\left(x-3\right)^2}{x^2-9}\\ b,\dfrac{x+1}{x-1}=\dfrac{\left(x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x-1\right)}=\dfrac{x^2-1}{\left(x-1\right)^2}\\ c,\dfrac{2x+1}{3x-2}=\dfrac{-\left(2x+1\right)}{-\left(3x-2\right)}=\dfrac{-2x-1}{2-3x}\\ d,-\dfrac{x-3}{1-2x}=\dfrac{x-3}{-\left(1-2x\right)}=\dfrac{x-3}{2x-1}\)