a. \(\dfrac{-6}{15}=\dfrac{-6:3}{15:3}=\dfrac{-2}{5}\)
Vậy \(\dfrac{-6}{15}\ne\dfrac{2}{-3}\)
b. \(\dfrac{-6}{-7}=\dfrac{-6.\left(-1\right)}{-7.\left(-1\right)}=\dfrac{6}{7}\)
Vậy: \(\dfrac{6}{7}=\dfrac{-6}{-7}\)
c. Ta có: \(\dfrac{5}{7}< 1\)
\(\dfrac{7}{5}>1\)
Vậy \(\dfrac{5}{7}\ne\dfrac{7}{5}\)