Question

bài 1: tìm x: 

a) x+(x+1)+(x+2)+.....+(x+2003)=2004

b) 7/3+(x-3/2)=(3-3/2).x

Answer 1

b.\(\frac{7}{3}+x-\frac{3}{2}=\frac{3}{2}x\)

\(\frac{5}{6}+x=\frac{3}{2}x\)

\(-\frac{1}{2}x=\frac{-5}{6}\)

\(x=\frac{5}{3}\)

Answer 2

a.

x+(x+1)+(x+2)+...+(x+2003)=2004

x+x+1+x+2+...+x+2003=2004

2004x+(2003+1)(2003/2)=2004

2004x=-2005002

x=-1000.5