\(UCLN\left(a;b\right)=3\\ \Rightarrow\left\{{}\begin{matrix}a⋮3\\b⋮3\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}a=3k\\b=3h\end{matrix}\right.\left(\left(k;h\right)=1\right)\)
Ta có :
\(a.b=36\\ \Rightarrow3k.3h=36\\ \Rightarrow9kh=36\\ \Rightarrow kh=4\)
Từ đây tìm k;h rồi tìm a;b
2.
\(2n+5⋮2n-1\\ \Rightarrow\left(2n-1\right)+6⋮2n-1\\ \Rightarrow6⋮2n-1\)