b: \(10A=\dfrac{10^6+10}{10^6+1}=1+\dfrac{9}{10^6+1}\)
\(10B=\dfrac{10^9+10}{10^9+1}=1+\dfrac{9}{10^9+1}\)
mà \(10^6+1< 10^9+1\)
nên A>B
c: \(10A=\dfrac{10^{200}+10}{10^{200}+1}=1+\dfrac{9}{10^{200}+1}\)
\(10B=\dfrac{10^{2000}+10}{10^{2000}+1}=1+\dfrac{9}{10^{2000}+1}\)
mà \(10^{200}+1< 10^{2000}+1\)
nên A>B