Đổi R= 50cm= 0,5m
a/ Có \(T=\frac{1}{n}\Rightarrow n=\frac{1}{T}=\frac{1}{1,2}=\frac{5}{6}\left(vong\right)\)
\(\omega=2n\pi=\frac{2.5}{6}.\pi=\frac{5}{3}\pi\left(rad/s\right)\)
b/ \(v=\omega.R=\frac{5}{3}\pi.0,5=\frac{5}{6}\pi\left(m/s\right)\)
\(a_{ht}=\frac{v^2}{R}=\frac{\frac{25}{36}\pi^2}{0,5}=\frac{25}{18}\pi^2\left(m/s^2\right)\)