Gọi d = ƯCLN(2n + 1; n + 1)
Ta có :
\(\left\{{}\begin{matrix}2n+1⋮d\\n+1⋮d\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2n+1⋮d\\2n+2⋮d\end{matrix}\right.\)
=> 2n + 2 - 2n - 1 \(⋮d\)
=> 1 \(⋮d\)
=> d = 1
=> đpcm
@Đậu Thị Khánh Huyền