\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy ....
\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy x = 0 hoặc \(x=\dfrac{1}{7}\)
\(2x.\left(x-\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow2x=0\Rightarrow x=0\)
\(\Leftrightarrow x-\dfrac{1}{7}=0\Rightarrow x=\dfrac{1}{7}\)
2x . ( x-\(\dfrac{1}{7}\)) = 0
=> 2x=0 hoặc x-\(\dfrac{1}{7}\)=0
=> x=0 hoặc x=\(\dfrac{1}{7}\)
Suy ra : x=0 hoặc x=\(\dfrac{1}{7}\)
