\(2x-\frac{1}{2}:\frac{3}{2}=3\left(1-x\right)+\frac{7}{4}\)
\(\Leftrightarrow2x-\frac{1}{3}=3-3x+\frac{7}{4}\)
\(\Leftrightarrow5x=3+\frac{7}{4}+\frac{1}{3}=\frac{61}{12}\)
\(\Leftrightarrow x=\frac{61}{60}\)
\(2x-\frac{1}{2}:\frac{3}{2}=3\left(1-x\right)+\frac{7}{4}\)
\(=>2x-\frac{1}{2}\cdot\frac{2}{3}=3\cdot1-3x+\frac{7}{4}\)
\(=>2x-\frac{1}{3}=3+\frac{7}{4}-3x\)
\(=>2x+3x=\frac{36}{12}+\frac{21}{12}+\frac{4}{12}\)
\(=>5x=\frac{61}{12}\)
\(=>x=\frac{61}{12}:5=\frac{61}{12}\cdot\frac{1}{5}=\frac{61}{60}\)
2x - 1/2 : 3/2 = 3(1-x) + 7/4
=> 2x-1/3 = 3-3x + 7/4
=> 5x= 3+ 7/4 +1/3 = 61/12
=> x = 61/60
