Question

b) 11/4 : ( 2*y +5/7) = 1/2

  

Answer 1

b)\(\frac{11}{4}:\left(2.y+\frac{5}{7}\right)=\frac{1}{2}\)

   \(\left(2.y+\frac{5}{7}\right)=\frac{11}{4}:\frac{1}{2}\)

   \(\left(2.y+\frac{5}{7}\right)=\frac{11}{2}\)

     \(2y=\frac{67}{14}\)

     \(y=\frac{67}{28}\)

Vậy \(y=\frac{67}{28}\)

Answer 2

\(\frac{11}{4}:\left(2y+\frac{5}{7}\right)=\frac{1}{2}\)

<=> \(\left(2y+\frac{5}{7}\right)=\frac{11}{4}:\frac{1}{2}=\frac{11}{4}.2=\frac{11}{2}\)

<=> \(2y=\frac{11}{2}-\frac{5}{7}=\frac{67}{14}\)

<=> y = 67/28

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Answer 3

\(\frac{11}{4}:\left(2y+\frac{5}{7}\right)=\frac{1}{2}\)

\(\Rightarrow2y+\frac{5}{7}=\frac{11}{4}:\frac{1}{2}\)

\(\Rightarrow2y+\frac{5}{7}=\frac{11}{2}\)

\(\Rightarrow2y=\frac{11}{2}-\frac{5}{7}\)

\(\Rightarrow2y=\frac{67}{14}\)

\(\Rightarrow y=\frac{67}{14}:2\)

\(\Rightarrow y=\frac{67}{28}\)

Vậy \(y=\frac{67}{28}\)