a/ \(Fe_2O_3\left(0,075\right)+3H_2\left(0,225\right)\rightarrow2Fe\left(0,15\right)+3H_2O\)
\(CuO\left(0,05\right)+H_2\left(0,05\right)\rightarrow Cu\left(0,05\right)+H_2O\)
\(\left\{{}\begin{matrix}m_{Fe_2O_3}=16.75\%=12\left(g\right)\\m_{CuO}=16.25\%=4\left(g\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}n_{Fe_2O_3}=\dfrac{12}{160}=0,075\left(mol\right)\\n_{CuO}=\dfrac{4}{80}=0,05\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow n_{H_2}=0,225+0,05=0,275\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,275.22,4=6,16\left(l\right)\)
b/ \(Fe\left(0,15\right)+H_2SO_4\rightarrow FeSO_4+H_2\left(0,15\right)\)
\(Cu\left(0,05\right)+H_2SO_4\rightarrow CuSO_4+H_2\left(0,05\right)\)
\(\Rightarrow n_{H_2}=0,15+0,05=0,2\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,2.22,4=4,48\left(l\right)\)
