Question

Ai giúp mình với ạ:((

Answer 1

ĐK: x ≥ 0; x ≠ 9

\(\dfrac{x-4\sqrt{x}+3}{\sqrt{x}-3}=\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}{\sqrt{x}-3}=\sqrt{x}-1\) 

Answer 2

\(\dfrac{x-4\sqrt{x}+3}{\sqrt{x}-3}=\sqrt{x}-1\)