`a)A` có nghĩa `<=>x-1 >= 0 <=>x >= 1`
`b)B=\sqrt{3^2 .2}+\sqrt{2^3}-\sqrt{5^2 .2}`
`<=>B=3\sqrt{2}+2\sqrt{2}-5\sqrt{2}`
`<=>B=0`
`c)` Với `a >= 0,a \ne 1` có:
`C=[a-1]/[\sqrt{a}-1]-[a\sqrt{a}-1]/[a-1]`
`C=[(a-1)(\sqrt{a}+1)-a\sqrt{a}+1]/[(\sqrt{a}-1)(\sqrt{a}+1)]`
`C=[a\sqrt{a}+a-\sqrt{a}-1-a\sqrt{a}+1]/[(\sqrt{a}-1)(\sqrt{a}+1)]`
`C=a/[a-1]`