Question

a)\((\)\(\dfrac{1}{9}\):\(\dfrac{8}{27}\)\()\):\(\dfrac{-1}{3}\)\(]\):\(\dfrac{81}{128}\) b)\((\)\(\dfrac{-7}{15}\)\()\).\(\dfrac{5}{8}\).\(\dfrac{15}{-7}\).\((\)-32\()\)

Answer 1

\(a )\)

\(\left[\left(\dfrac{1}{9}:\dfrac{8}{27}\right):\dfrac{-1}{3}\right]:\dfrac{81}{128}\)

\(=\left[\left(\dfrac{3}{27}:\dfrac{8}{27}\right):\dfrac{-1}{3}\right]:\dfrac{81}{128}\)

\(=\left(\dfrac{3}{8}:\dfrac{-1}{3}\right):\dfrac{81}{128}\)

\(=\dfrac{9}{-8}:\dfrac{81}{128}=\dfrac{9}{-8}.\dfrac{128}{91}=\dfrac{16}{-9}\)

\(b) \)

\(\left(\dfrac{-7}{15}\right).\dfrac{5}{8}.\left(\dfrac{15}{-7}\right).\left(-32\right)\)

\(=\dfrac{-7.5.15}{15.8.-7}.\left(-32\right)\)

\(=\dfrac{5}{8}.\left(-32\right)\)

\(=-20\)

Answer 2

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