\(A=1+2^2+2^4+...+2^{2014}+2^{2016}\)
\(\Rightarrow4A=2^2+2^4+...+2^{2016}+2^{2018}\)
\(\Rightarrow4A-A=\left(2^2+2^4+...+2^{2016}+2^{2018}\right)-\left(1+2^2+2^4+...+2^{2016}\right)\)
\(\Rightarrow3A=2^{2018}-1\)
\(\Rightarrow A=\frac{2^{2018}-1}{3}\)
Vậy \(A=\frac{2^{2018}-1}{3}\)