a) M CuSO4=64+32+16.4=160 đvC
b) MCaSOa=40+32+16.a=130
=>a=4
a: \(M_{CO_2}=12+16\cdot2=44\)
\(M_{CuSO_4}=64+32+16\cdot4=192\)
b: Theo đề, ta có: \(40+32+16\cdot a=120\)
=>16a=120-32-40=80-32=48
=>a=3
a, \(CO_2\)\(=12+\left(16.2\right)\)=44(dvC)
\(CuSO_4\)=64+32+(16.4) =160(dvC)