b) \(\dfrac{x-12}{4}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{x-12}{4}=\dfrac{2}{4}\)
\(\Rightarrow x-12=2\)
\(\Leftrightarrow x=2+12\)
\(\Leftrightarrow x=14\)
c) \(1< \dfrac{x}{3}< 2\)
\(\Rightarrow\dfrac{3}{3}< \dfrac{x}{3}< \dfrac{6}{3}\)
\(\Rightarrow x\in\left\{4;5\right\}\)
Vậy \(x\in\left\{4;5\right\}\)