P = (x-1)(2x+3)
=> P=2x2+3x-2x-3
=> P=2x2+x-3
=> P=\(2x^2+x+\dfrac{1}{8}-\dfrac{25}{8}\)
=> P=2\(\left(x^2+\dfrac{1}{2}x+\dfrac{1}{16}\right)-\dfrac{25}{8}\)
=> P=\(2\left(x+\dfrac{1}{4}\right)^2-\dfrac{25}{8}\)
=> min P =\(\dfrac{-25}{8}\) khi \(x+\dfrac{1}{4}=0\Rightarrow x=-\dfrac{1}{4}\)