ta có :3x=4y,5y=6z
=>\(\dfrac{x}{4}\)=\(\dfrac{y}{3}\); \(\dfrac{y}{6}\)=\(\dfrac{z}{5}\)
=> \(\dfrac{x}{8}\)=\(\dfrac{y}{6}\); \(\dfrac{y}{6}\)=\(\dfrac{z}{5}\)
=> \(\dfrac{x}{8}\)=\(\dfrac{y}{6}\)=\(\dfrac{z}{5}\)
Đặt \(\dfrac{x}{8}\)=\(\dfrac{y}{6}\)=\(\dfrac{z}{5}\)=k
=> x=8k ; y=6k ; z=5k
=> 8k.6k.5k=30
=> 240k3 =30
=>k3 =8
=>k=2
=> x=8.2=16 ; y=6.2=12 ; x =5.2=10