a/ \(=\lim\limits_{x\rightarrow-\infty}\dfrac{\dfrac{3x^4}{x^4}-\dfrac{2x^5}{x^4}}{\dfrac{5x^4}{x^4}+\dfrac{x}{x^4}+\dfrac{4}{x^4}}=+\infty\)
b/ \(=\lim\limits_{x\rightarrow+\infty}\dfrac{\dfrac{x}{x}-\dfrac{1}{x}}{\sqrt{\dfrac{x^2}{x^2}-\dfrac{1}{x^2}}}=1\)
a) lim \(\dfrac{2x-\sqrt{3x^2+2}}{5x+\sqrt{x^2+2}}\)
x-> +∞
b) lim \(\sqrt{\dfrac{x^2+1}{2x^4+x^2-3}}\)
x-> ∞
a) lim ( \(\sqrt{x^2-x+1}-\sqrt{x^2+x+1}\)
x-> +∞
b) lim \(\dfrac{\sqrt{4x+1}-3}{x^2-4}\)
x-> 2
c) lim \(\dfrac{\sqrt{2x+5}-1}{x^2-4}\)
x-> -2
a) lim \(\dfrac{x\sqrt{x^2+1}-2x+1}{^3\sqrt{2x^3-2}+1}\)
x-> -∞
b) lim \(\dfrac{\left(2x+1\right)^3\left(x+2\right)^4}{\left(3-2x\right)^7}\)
x-> -∞
c) lim \(\dfrac{\sqrt{4x^2+x}+^3\sqrt{8x^3+x-1}}{^4\sqrt{x^4+3}}\)
x-> +∞
Tìm giơi han:
a) lim (x-> \(+\infty\)) \(\dfrac{\sqrt{x^2+1}+x}{5-2x}\)
b) lim (x->4) \(\left(\dfrac{\sqrt{15x+4}-\sqrt{x-3}-3}{-x+4}\right)\)
sorry, e k bt nhâp lim ..
lim x\(\sqrt{\dfrac{x^2+1}{2x^4+x^2-3}}\)
x-> +∞
gioi hạn \(\lim\limits_{x\rightarrow1}\dfrac{x+2-\sqrt{7x+2}}{x-\sqrt{5x-4}}=\dfrac{a}{b}\). (ps tôi giản) Tìm các gia trị thưc a,b?
lim \(\dfrac{-2x^5+x^4-3}{3x^2-7}\)
x-> -∞
lim \(\dfrac{^3\sqrt{x+1}-1}{^{^4\sqrt{2x+1}-1}}\)
x-> 1
\(\lim\limits_{x\rightarrow1}\dfrac{3-2x^2-x^4}{5-3x-2x^2}\)
