Question

a) \(\left|x+2\right|\) = 2 - x

b)\(\left|x+3\right|\) =x + 3

Tìm x hộ mình với

Answer 1

a) |x+2|= 2-x

=> x+2=-(2-x) (1)

x+2=2-x (2)

(1)=> x+2=-2+x=>x+2=x-2

=> x vô nghiệm

(2)=> x+2=2-x => 2x=0

=> x=0

b)|x+3|=x+3

=> x+3=-(x+3) (1)

x+3=x+3 (2)

(1)=> x+3=-x-3 => 2x= -6

=> x= -3

(2)=> x+3=x+3 => x vô số nghiệm=> x thuộc Z

Answer 2

a. Ta có: \(\left|x+2\right|=2-x\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+2=2-x\\x+2=-\left(2-x\right)\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+x=2-2\\x+2=-2+x\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x=0\\x+2=x-2\left(vông\text{h}iệm\right)\end{matrix}\right.\)

\(\Rightarrow x=0\)

Vậy x=0