Question

a) Chứng minh: \(\frac{1}{a\left(a+1\right)}=\frac{1}{a}+\frac{-1}{a+1}\)(a ∈ N*)

b) Tính: B =\(\frac{11}{5.7}+\frac{11}{7.9}+\frac{11}{9.11}+...+\frac{11}{59.61}\)

Các bạn giúp mình với! Mai mình phải nộp bài rồi:(((

Answer 1

a,Ta có : \(\frac{1}{a}+\frac{-1}{a+1}=\frac{1}{a}-\frac{1}{a+1}\)

=\(\frac{a+1-a}{a\left(a+1\right)}=\frac{1}{a\left(a+1\right)}\)(Đpcm)

b,\(\frac{11}{5.7}+\frac{11}{7.9}+\frac{11}{9.11}+.....+\frac{11}{59.61}\)

=\(\frac{11}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+.....+\frac{2}{59.61}\right)\)

=\(\frac{11}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+......+\frac{1}{59}-\frac{1}{61}\right)\)

=\(\frac{11}{2}.\left(\frac{1}{5}-\frac{1}{61}\right)=\frac{308}{305}\)