Question

a)\(\left(\frac{9}{2}-3x\right)\cdot\frac{-11}{7}=\frac{11}{14}\)

b)\(\frac{7}{3}x-x=\frac{-3}{2}\)

Answer 1

a)\(\left(\frac{9}{2}-3x\right)\cdot\frac{-11}{7}=\frac{11}{14}\)

\(\Leftrightarrow3\left(\frac{3}{2}-x\right)=\frac{11}{14}\cdot-\frac{-7}{11}\)

\(\Leftrightarrow\frac{3}{2}-x=-\frac{1}{2}\cdot\frac{1}{3}\)

\(\Leftrightarrow-x=-\frac{1}{6}-\frac{3}{2}=-\frac{5}{3}\)

\(\Leftrightarrow x=\frac{5}{3}\)

b)\(\frac{7}{3}-x=-\frac{3}{2}\)

\(\Leftrightarrow\frac{4}{3}x=-\frac{3}{2}\)

\(\Leftrightarrow x=-\frac{3}{2}\cdot\frac{3}{4}\)

\(\Leftrightarrow x=-\frac{9}{8}\)

Answer 2

a)\(\dfrac{25}{12}\)