Ta có: \(\left(3x-2\right)\left(4x+5\right)=0\)
\(< =>\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\)
\(< =>\left[{}\begin{matrix}3x=2\\4x=-5\end{matrix}\right.\)
\(< =>\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{matrix}\right.\)
Vậy x=\(\dfrac{2}{3}\) hoặc x=\(-\dfrac{5}{4}\)
Chúc bn học tốt!
a) 5-4x=3x-9
b) (x-4)(3x+9)=0
c) (x/(x+4))+(12/(x-4))=(4x+48)/(x*x-16)
d) 4-2x=7-x
e) (x+4)(8-4x)=0
f) (x/(x+5))+(11/(x-5))=(x+55)/(x*x-25)
g) ((3x+2)/2) - ((3x+1)/6)= (5/3) +2x
h) 2x-(3-5x)=4(x+3)
i) 3x -6+x=9-x
k) 2t-3+5t= 4t+12
m.n giúp mik ạ ...
1. a. 4x-20=0
b. 2x+x+12=0
c. x-5=3-x
d. 7-3x=9-x
2.
a. 7+2x=22-3x
b. 8x-3=5x+12
c. x-12+4x=25+2x-1
d. x+2x+3x-19=3x+5
e. 7-(2x+4)=-(x+4)
f. (x-1)-(2x-1)=9-x
a/4x-3/x-5=29/3
b/2x-1/5-3x=2
c/4x-5/x-1=2+ x/x-1
d/7/x+2=3/x-5
e/2x+5/2x-x/x+5=0
giải phương trình
a) \(\frac{4x-17}{2x^2+5}=0\)
b) \(\frac{\left(x^2-2x\right)-\left(3x+6\right)}{x+2}=0\)
c) \(\frac{x^2-x-6}{x-3}=0\)
d) \(\frac{2x-5}{x+5}=3\)
e) \(\frac{5}{3x+2}=2x-1\)
1) Giải các pt chứa ẩn ở mẫu:
a) \(\frac{x-9}{x}-\frac{x}{x-9}=0\)
b) \(\frac{x+3}{x-2}=\frac{5}{\left(x-2\right)\left(3-x\right)}\)
c) \(\frac{x}{3x-2}-\frac{x}{4x-3}=\frac{x^3}{\left(3x-2\right)\left(4x-3\right)}\)
d) \(\frac{x}{x-5}-\frac{x-5}{x}=0\)
Giải các PT sau:
a,4x-3/x-5=29/3
b,2x-1/5-3x=2
c,4x-5/x-1=2+x/x-1
d,7/x+2=3/x-5
e,2x+5/2x-x/x+5=0
f,12x+1/11x-4+10x-4/9=20x+17/18
Giải các PT sau:
a,(5x-4)(4x+6)=0 b,(3,5x-7)(2,1x-6,3)=0
c,(4x-10)(24+5x)=0 d,(x-3)(2x+1)=0
e,(5x-10)(8-2x)=0 f,(9-3x)(15+3x)=0
\(a,\dfrac{1}{x^2+3x+2}-\dfrac{3}{x^2-x-2}=\dfrac{-1}{x^2-4}\)
\(b,\dfrac{2x-1}{x^2+4x-5}+\dfrac{x-2}{x^2-10x+9}=\dfrac{3x-12}{x^2-4x-45}\)
giải giúp mình hai câu này của phuong trình chứa ẩn ơ mẫu
A) x^2 - 4x =0
B)5/x-2 - 3/x+2 = 3x - 1/x^2-4
