b)\(\frac{2x-1}{x-1}+\frac{x}{\left(x-1\right)\left(x-2\right)}=\frac{6x-2}{x-2}\)
\(< =>\left(2x-1\right)\left(x-2\right)+x-\left(6x-2\right)\left(x-1\right)=0\)
\(< =>2x^2-x-4x+2+x-\left(6x^2-2x-6x+2\right)=0\)
\(< =>2x^2-4x+2-6x^2+8x-2=0\)
\(< =>-4x^2+4x=0\)
\(< =>-4x\left(x+1\right)=0\)
\(TH1:-4x=0< =>x=0\) \(TH2:x+1=0< =>x=-1\)
\(S=\left\{-1;0\right\}\)
ai giúp mik với mik nhiều bt lắm
a, 1/x-1 - 7/x+2 = 3/x2+x-2
b,x+3/x-4 + x-1/x-2 = 2/6x-8-x2
c,1/x+1 + 2/x3-x2x+1 = 3/1-x2
d, 3x-1/x-1 - 2x+5/x+3 = 1 - 4/x2+2x-3
e, x2+2x+1/x2+2x+2 + x2+2x+2/x2+2x+3 = 7/6
f, 1/4x2-12x+9 - 3/9-4x2=4/4x2+12x+9
Giải phương trình:
b)4x/x2+4x+3 - 1=6(1/x+3 - 1/2x+2)
c)x2-x-12=0
e)6x+22/x+2 - 2x+7/x+3=x+4/x^2+5x+6
bài 1 :giải pt
a, 2/x2+2x+1 - 5/x2-2x+1 = 3/1-x3
bài 2 giải pt
a, x2+2x+2/x-1 + x2+8x+20= x2 +4x +6/ x+2 + x2+6x +12/x+3
giúp mình với tối đi hoc rồi
Help me... Giup đk chừng nào hay chừng đó ạ.
Bài 1:a, \(\dfrac{x}{x-1}-\dfrac{2x}{x^2-1}=0\)
b, \(\dfrac{\left(x+2\right)^2}{2x-3}-1=\dfrac{x^2+10}{2x-3}\)
c,\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
d,\(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)
e,\(\dfrac{3}{5x-1}+\dfrac{2}{3-5x}=\dfrac{4}{\left(1-5x\right)\left(5x-3\right)}\)
f,\(\dfrac{3}{1-4x}=\dfrac{2}{4x+1}-\dfrac{8+6x}{16x^2-1}\)
g,\(\dfrac{y-1}{y-2}-\dfrac{5}{y+2}=\dfrac{12}{y^2-4}+1\)
h,\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\)
i,\(\dfrac{2x-3}{x+2}-\dfrac{x+2}{x-2}=\dfrac{2}{x^2-4}\)
j,\(\dfrac{x-1}{x^2-4}=\dfrac{3}{2-x}\)
a) 5-4x=3x-9
b) (x-4)(3x+9)=0
c) (x/(x+4))+(12/(x-4))=(4x+48)/(x*x-16)
d) 4-2x=7-x
e) (x+4)(8-4x)=0
f) (x/(x+5))+(11/(x-5))=(x+55)/(x*x-25)
g) ((3x+2)/2) - ((3x+1)/6)= (5/3) +2x
h) 2x-(3-5x)=4(x+3)
i) 3x -6+x=9-x
k) 2t-3+5t= 4t+12
m.n giúp mik ạ ...
Giải các phương trình sau :
a) \(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2+1\right)}{x^2-4}\)
b) \(1+\dfrac{x}{3-x}=\dfrac{5x}{\left(x+2\right)\left(3-x\right)}+\dfrac{2}{x+2}\)
c) \(\dfrac{2}{x-1}+\dfrac{2x+3}{x^2+x+1}=\dfrac{\left(2x-1\right)\left(2x+1\right)}{x^3-1}\)
d) \(\dfrac{x^3-\left(x-1\right)^3}{\left(4x+3\right)\left(x-5\right)}=\dfrac{7x-1}{4x+3}-\dfrac{x}{x-5}\)
Giải phương trình:
a/ \(1+\dfrac{x}{3-x}=\dfrac{5x}{\left(x+2\right)\left(x+3\right)}+\dfrac{2}{x+2}\)
b/ \(\dfrac{x+2}{x-2}-\dfrac{2}{x^2-2x}=\dfrac{1}{x}\)
c/ \(\dfrac{x}{2x+2}-\dfrac{2x}{x^2-2x-3}=\dfrac{2}{6-2x}\)
d/ \(\dfrac{5}{-x^2+5x-6}+\dfrac{x+3}{2-x}=0\)
giải các bất pt sau:
a, 4x-10<0
b, 2x+x+12\(\ge0\)
c, x-5\(\ge3-x\)
d, 7-3x>9-x
đ, 2x-(3-5x)\(\le4\left(x+3\right)\)
e, 3x-6+x<9-x
f, 2t-3+5t\(\ge\)4t+12
g, 3y-2\(\le2y-3\)
h,3-4x+24+6x\(\ge x+27+3x\)
i, 5-(6-x)\(\le4\left(3-2x\right)\)
k, 5(2x-3)- 4(5x-7)\(\ge19-2\left(x+11\right)\)
l, \(\dfrac{2x-5}{3}-\dfrac{3x-1}{2}< \dfrac{3-x}{5}-\dfrac{2x-1}{4}\)
m, \(5x-\dfrac{3-2x}{2}>\dfrac{7x-5}{2}+x\)
n, \(\dfrac{7x-2}{3}-2x< 5-\dfrac{x-2}{4}\)
