Question

a, 25-(2.x+10)=5

b, x-320:32=25.16

c,2448:[ 199-(x-6)]=24

d, 280-x.9 - x=80

Answer 1

a: =>2x+10=20

=>2x=10

hay x=5

b:=>x-10=400

hay x-410

d: =>280-10x=80

=>10x=200

hay x=20

Answer 2

a) \(25-\left(2x+10\right)=5\)

\(2x+10=25-5\)

\(2x+10=20\)

\(2x=20-10\)

\(2x=10\)

\(x=\dfrac{10}{2}\)

\(x=5\)

Vậy \(x=5\)

b) \(x-320:32=25.16\)

\(x-10=200\)

\(x=200+10\)

\(x=210\)

Vậy \(x=210\)

c) \(2448:\left[199-\left(x-6\right)\right]=24\)

\(199-\left(x-6\right)=2448:24\)

\(199-\left(x-6\right)=102\)

\(x-6=199-102\)

\(x-6=97\)

\(x=197+6\)

\(x=203\)

Vậy \(x=203\)

d) \(280-x.9-x=80\)

\(x.\left(9+1\right)=280-80\)

\(x.10=200\)

\(x=200:10\)

\(x=20\)

Vậy \(x=20\)