Ta có: \(\dfrac{9}{7}-\left|\dfrac{3}{2}x+\dfrac{2}{3}\right|=-\dfrac{1}{8}\)
\(\Leftrightarrow\left|\dfrac{3}{2}x+\dfrac{2}{3}\right|=\dfrac{79}{56}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{2}x+\dfrac{2}{3}=\dfrac{79}{56}\\\dfrac{3}{2}x+\dfrac{2}{3}=-\dfrac{79}{56}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{2}x=\dfrac{125}{168}\\\dfrac{3}{2}x=\dfrac{-349}{168}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{125}{252}\\x=\dfrac{-349}{252}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{125}{252};\dfrac{-349}{252}\right\}\)
9/7-|3/2x+2/3|=-1/8
|3/2 x +2/3| = 9/7 + 1/8
|3/2 x +2/3| = 79/56
TH1: 3/2 x +2/3 = 79/56
3/2 x = 125/168
x = 125/252
TH2: 3/2 x + 2/3 = -79/56
3/2 x = -349/168
x= -349/252
