\(n_{Ca\left(OH\right)_2}=0,25.0,2=0,05\left(mol\right)\)
\(n_{Ca}=\frac{8}{40}=0,2\left(mol\right)\)
\(n_{CaO}=\frac{5,6}{56}=0,1\left(mol\right)\)
PTHH: \(Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
______0,2-------------------->0,2___________(mol)
\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
0,1-------------------->0,1___________(mol)
=> \(n_{Ca\left(OH\right)_2}=0,1+0,2+0,05=0,35\left(mol\right)\)
=> \(C_M=\frac{0,35}{0,25}=1,4M\)
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