=81*(27+9^15):(3^5+3^32)
\(=\dfrac{3^4\cdot\left(3^3+3^{30}\right)}{3^5+3^{32}}=\dfrac{3^7\left(1+3^{27}\right)}{3^5\left(1+3^{27}\right)}=\dfrac{3^7}{3^5}=9\)
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