Ta có: \(7\cdot2^{13}-2^{15}\)
\(=2^{13}\cdot\left(7-2^2\right)\)
\(=3\cdot2^{13}\)
Ta có: \(2\cdot3^{16}-17\cdot3^{14}\)
\(=3^{14}\cdot\left(2\cdot3^2-17\right)\)
\(=3^{14}\cdot\left(18-17\right)=3^{14}\)
\(=3\cdot3^{13}>3\cdot2^{13}=7\cdot2^{13}-2^{15}\)