65- 5( x+11) =10
=> 5( x+11) = 65- 10
=> 5( x+11) = 55
=> x+ 11= 55: 5
=> x+ 11= 11
=> x= 11- 11
=> x= 0
Vậy x= 0
\(65-5\left\{x+11\right\}=10\\ =>5\left\{x+11\right\}=55\\ =>x+11=11\\ =>x=0\)
65-5( X+11)=10
\(\Leftrightarrow\)5( X+11)=65-10
\(\Leftrightarrow\)5(X+11)=55
\(\Leftrightarrow\)X+11=55\(_{\div}\)5
X+11=11
X=0